80=-16t^2-112

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Solution for 80=-16t^2-112 equation: 



80=-16t^2-112

We move all terms to the left:

80-(-16t^2-112)=0

We get rid of parentheses

16t^2+112+80=0

We add all the numbers together, and all the variables

16t^2+192=0

a = 16; b = 0; c = +192;
Δ = b2-4ac
Δ = 02-4·16·192
Δ = -12288
Delta is less than zero, so there is no solution for the equation

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